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0.04x^2+3.28x=0
a = 0.04; b = 3.28; c = 0;
Δ = b2-4ac
Δ = 3.282-4·0.04·0
Δ = 10.7584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.28)-\sqrt{10.7584}}{2*0.04}=\frac{-3.28-\sqrt{10.7584}}{0.08} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.28)+\sqrt{10.7584}}{2*0.04}=\frac{-3.28+\sqrt{10.7584}}{0.08} $
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